DOTHAN, Ala. (WDHN) — According to the Centers for Disease Control and Prevention, Alabama is one of 35 states in the nation experiencing a small outbreak of salmonella.
The CDC has reported a total of 419 cases of salmonella during this outbreak. Alabama is listed as having between 1 to 5 cases of salmonella.
According to Jessie White a registered dietician, salmonella is often found in eggs, poultry, milk products, and produce.
White said salmonella can spread through cross-contamination. She tells WDHN News proper food preparation is crucial in preventing salmonella infection. That includes cooking food at appropriate temperatures, properly handling food, and making sure you wash your hands during the process.
“Anytime you play with animals, salmonella is found in the GI tract of humans and animals,” White said. “Make sure if you are picking up after your dog or your cat make sure you wash your hands really well after. Wash your hands after using the restroom, it’s really a lot of a hygiene thing.”
White also says the CDC has guidelines for the appropriate cooking temperatures on its website.